You throw a ball with a speed of 25.0 m/s at an angle of 40.0â—¦ above the horizontal directly toward a wall. the wall is 22.0 m from the release point of the ball. how long does the ball take to reach the wall?

The ball takes about 1.15 seconds to reach the wall

Acceleration is rate of change of velocity.

a = acceleration ( m/s² )

v = final velocity ( m/s )

u = initial velocity ( m/s )

t = time taken ( s )

d = distance ( m )

Let us now tackle the problem!

This problem is about Projectile Motion

Given:

initial speed = u = 25 m/s

angle of speed = θ = 40.0°

horizontal distance = x = 22.0 m

Unknown:

time taken by the ball = t = ?

Solution:

We will use this following formula to find the time taken by the ball to reach the wall:

The ball takes about 1.15 seconds to reach the wall

Grade: High School

Subject: Physics

Chapter: Kinematics

Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Projectile , Motion , Horizontal , Vertical , Release , Point , Ball , Wall

+15-35=-20

going in opposite directions