Four rods that obey hooke's law are each put under tension. (a) a rod 50.0 cm long with cross-sectional area 1.00 mm2 and with a 200 n force applied on each end. a rod 25.0 cm long with cross-sectional area 1.00 mm2 and with a 200 n force applied on each end. 00 mm2 and with a 100 n on each end. (c) a rod 20.0 cm long with cross-sectional area 2 force applied order the rods according to the tensile stress on each rod, from smallest to largest. oc

   c <  a = b

Explanation:

to arrange tensile stress from smallest to largest

tensile stress =

a) A rod 50.0 cm long with cross-sectional area 1.00 mm² and with a 200 N force applied on each end.

b) A rod 25.0 cm long with cross-sectional area 1.00 mm² and with a 200 N force applied on each end.

c) A rod 20 cm long with cross-sectional area 2.00 mm² and with a 100 N force applied on each end.

hence the order comes out to be

   c <  a = b

1 a

2 b

3 b

4 d

5 d

6 d

explanation:

the simple machine has three main features. they are:

fulcrum is the center point or pivot point of the machine. effort is input force/ applied force. load is external force/ output.

the keisha 's machine labels are

x : load

y: fulcrum

z: lever