Apipe with cross-sectional area 2.0 m^2 is joined to a second pipe with cross-sectional area 0.5 m^2. the pipes are both completely filled with water. the water in the 2.0 m^2 pipe is flowing into the smaller pipe with a speed of 2 m/s. how fast is the water flowing in the second pipe?

a.) 8 m/s

b.) 0 m/s

c.) 4 m/s

d.) 2 m/s

Explanation:

It is given that,

Area of cross section of the pipe,

Area of cross section of the another pipe,

Speed of water in first pipe,

To find,

Speed of the water flowing in the second pipe.

Solve,

Let is the speed of water flowing in the second pipe. The relation between the area of cross section and the velocity is given by the continuity equation. It is given by :

Therefore, the water is flowing in the second pipe at the rate of 8 m/s.

a.) 8 m/s

Explanation:

Given that

A₁= 2 m²

V₁= 2 m/s

A₂=0.5 m²

Lets take speed in 0.5m² is V₂

As given that both pipes are connected in the series that is volume flow rate will be same

Q= A₁V₁ = A₂V₂

Now by putting the values

A₁V₁ = A₂V₂

2 x 2 = 0.5 x V₂

V₂= 8 m/s

a.) 8 m/s

diagram is missing, but i will try to explain your doubt.

answer:

amplitude is the maximum displacement or distance moved on a point of a vibrating body or wave measured from its equilibrium position.it is equal to half the length of vibration path.

the answer is 3.1 his answer is wrong mines is right