Iam confused on how to do either of these problems.

19. a) 48.3 m

     b) 88.2 m

20. a) t ≅ 6.38 s

      b) ≅270.1 m

Explanation:

Use basic linear motion equations for each of these questions, correctly.

s = ut + a

a) applying the equation to the horizontal direction,

s = ut = 11.5×4.2 = 48.3 m ( as gravitational acceleration for horizontal direction is zero)

b) applying the equation to the vertical direction in downward direction,

     s = h( height ) =0 + g ( as initial velocity in vertical direction is zero.)

           h = 0.5×10×

              =88.2 m

20) Using the same equation,

a)  s = ut + a apply it for vertical motion just as it reachs the ground in upwards direction,

0 = usin37°t - g

53(0.6081) = 0.5×10×t

t ≅ 6.38 s

b) again same equation in horizontal direction,

s = ucos37°t = 53×0.7986×6.38

  ≅270.1 m