Section #5
position - time graph
posson )
8 8 8 8
#15) no movement:
#16) walking away from origin:
#17) fastest speed:
#18) direction changes:
#19) negative slope:
#20) positive slope:
#21) total distance:
#22 total displacement:
g
40
20
60
time (sec)
section #6
velocity - time graph
velocity
(m/min)
8 8 8 8
#23) no movement:
#24) positive velocity:
#25) decreasing velocity:
#26) no acceleration:
#27) total distance:
#28) total displacement:
#29) most acceleration:
#30) increasing velocity:
time
(min)
8 8
40

answer: the metamorphic rocks are formed when they are exposed to high pressure and high temperatures. this happens when one of the earth's plates comes in contact with the other plate by traveling in opposite directions, straight into each other or slipping under one another. the friction that is caused by this activity results in   melting of rocks and when it cools they are known as metamorphic rocks. this process needs a controlled amount of pressure and temperature otherwise it may turn into magma.

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

where is unknown. because the position is parabolic, there is symmetry about the midpoint at , and we know that

so that the position function is

which means the velocity is

then the total distance traveled is

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at and ends at , so its displacement is 0.