Acar traveling at 54km/hr slows down uniformly to a velocity of 18km/hr when the break were gradually applied. 1.how long does it takes to cover a distance of 50m 2. what is the deceleration?

1. 5 s

2. -2 m/s²

Explanation:

Given:

v₀ = 54 km/hr = 15 m/s

v = 18 km/hr = 5 m/s

Δx = 50 m

1. Find: t

Δx = ½ (v + v₀) t

(50 m) = ½ (5 m/s + 15 m/s) t

t = 5 s

2. Find: a

v² = v₀² + 2aΔx

(5 m/s)² = (15 m/s)² + 2a (50 m)

a = -2 m/s²

f=ma a/f/m a= 480/60 a = 8m/s/s that is quick wow

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