If an object is projected upward from ground level with an initial velocity of 160 ft per sec, then its height in feet after t seconds is given by
s(t)=-16t^2+ 160t. find the number of seconds it will take to reach its maximum height. what is this maximum height?

Time will be 5 sec

And maximum height will be 1200 feet    

Explanation:

We have given that initial velocity of the object u = 160 ft/sec'

Function of height

Take derivative of the distance

We know that first derivative of distance is velocity

So

At maximum height we know that velocity is zero

So

t = 5 sec

So it will take 5 sec to reach maximum height

Now maximum height will occur at t = 5 sec

So maximum height =

15.3 cos 65 degrees trig

like poles repel so keep pushing north to north and repels funny to see this