Acircular wire loop of radius 14.1 cm carries a current of 2.34 a. it is placed so that the normal to its plane makes an angle of 49.2° with a uniform magnetic field of magnitude 12.6 t. (a) calculate the magnitude of the magnetic dipole moment of the loop in amperes-square meters. (b) what is the magnitude of the torque acting on the loop?

(a)  

(b) 1.3927 Nm

Explanation:

We have given that radius

Current i = 2.34 A

Angle

Uniform magnetic field B = 12.6 T

Area is given by

(A) We know that magnetic dipole moment is given by , here i is current and A is area

So magnetic moment

(b) We know that torque is given by

So torque experienced by coil will be

the displacement produced by the body.  

the amount of force subjected to the body.  

the angle between the direction of force and displacement

answer: a. same unit

explanation: