Amachine carries a 4.0 kg package from an initial position of di = (0.50 m) + (0.75 m) + (0.20 m) at t = 0 to a final position of df = (7.20 m) + (13.0 m) + (7.30 m) at t = 11 s. the constant force applied by the machine on the package is f = (2.00 n) + (4.00 n) + (6.00 n) . (a) for that displacement, find the work done on the package by the machine's force. j (b) also, find the power of the machine's force on the package. w

a)

b)

Explanation:

The work is defined as:

when the force is on the same direction of the movement.

We need to calculate the displacement in each direction, so:

now having the displacement, we can calculate the work done by the machine:

The total work is the sum of each of them:

and the power is given by:

in simple terms, the principle states that the buoyancy force on an object is equal to the weight of the fluid displaced by the object, or the density of the fluid multiplied by the submerged volume times the gravitational acceleration, g. this is also known as upthrust.