An 80 kg person stands 0.75 m from the bottom of a ladder (i. e. d = 0.75 m). the ladder leans against a frictionless wall at a 60° angle. if the ladder is 50 kg and is 2.5 m long what is the friction due to the floor, in newtons, on the ladder?

the ladder in the previous problem had a person standing on it. assume this person climbs up so that he stands 2.0 m from the bottom of a ladder (i. e. d = 2.0 m). what is the force exerted by the wall, in newtons, on the ladder?

hi there!

out of the two, (b) precision would be more reasonable.   however, both a and b could be pretty reasonable.

-awesomerepublic   : )

d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day