If an electron is accelerated from rest through a potential difference of 9.9 kv, what is its resulting speed?

e=1/60 x 10^-19 c
k=8.99 x10^9
me=9.11 x 10^-31

Speed of the electron will be

Explanation:

We have given that charge on electron

Mass of electron

Potential difference =

Now according to energy conservation

the higher the current the higher the mag field around it the higher the influence on the compass

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