How long (in s) will it take an 825 kg car with a useful power output of 36.0 hp (1 hp = 746 w) to reach a speed of 17.0 m/s, neglecting friction? (assume the car starts from rest.) s (b) how long (in s) will this acceleration take if the car also climbs a 3.20 m-high hill in the process?

a)4.4s

b)5.4s

Explanation:

a) power =

for a body in motion

workdone =ΔK.E= mv₂² ₋

v₂=final velocity=17m/s

v₁=initial velocity=0m/s

m=mass of car=825kg

work done=×825×17² -  

work done=119212.5J

from question,

power=36×746=26856W

26856=119212.5÷time

time=119212.5÷26856

time=4.4s

b) the car is experiencing two forms of energy

workdone =  mv₂² + mgh

woekdone=  ×825×17² + 825×9.8×3.2

=119212.5 + 25,872= 145,084.5‬J

time = workdone ÷ power

=145084.5 ÷ 26856

=5.4s

true

explanation:

speed

ratio of distance traveled to time interval

net force

vector sum of forces on object

object

source of diverging light rays either luminous or illuminated

don't remove my answer im trying my best to answer them

explanation: