Water flowing in a horizontal 25-cm-diameter pipe at 10 m/s and 350 kpa gage enters a 90° bend reducing section, which connects to a 17-cm-diameter vertical pipe. the inlet of the bend is 50 cm above the exit. neglecting any frictional and gravitational effects, determine the net resultant force exerted on the reducer by the water. take the momentum-flux correction factor to be 1.04.

explanation:

could i give you a exaplo that could you?

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards

conservation of mass

mass before something happens = mass afterwards

the tires are rotating at 0.434 rpmlinear speed=45 m/sdiameter=0.550 mradius=0.275 mnow v= rωω= v/rω=45/0.275ω=163.6 rad/sω=163.6 rad/s (1rev/2π rad) (60s/1m)ω=1563 rpm