Calculate the root mean square velocity of nitrogen molecules at 25°c.

515.22 m/s

Explanation:

Formula for root mean square velocity is SQRT (3RT/M)

Where,

R = Rydberg's constant = 8.314 Kg. m²/ s². K. mol

T = Temperature in Kelvin

M = Molar mass in Kg/mol

First calculate molar mass,

As nitrogen is diatomic molecule,

Its molar mass is

M = 2(14) = 28 g/mol

Convert unit into Kg/mol

28 g/mol x 1 Kg/1000g = 2.8x10¯² Kg/mol

Convert temperature into kelvin

T = 25 + 273 = 298K

Put all values in formula

Vrms = SQRT (3RT/M)

Vrms = SQRT (3x8.314x298/2.8x10¯²)

Vrms = SQRT (265454. 14)

Vrms = 515.22 m/s

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz

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