You can shoot an arrow straight up so that it reaches the top of a 25-m-tall building. (a) how far will the arrow travel if you shoot it horizontally while pulling the bow in the same way? the arrow starts 1.45 m above the ground. (b) where do you need to put a target that is 1.45 m above the ground in order to hit it if you aim 30° above the horizontal? (c) determine the maximum distance that you can move the target and hit it with the arrow.

Part a)

Part b)

Part c)

Explanation:

As we can throw the arrow to maximum height of 25 m

so we will have

so we will have

Part a)

If arrow is shot from 1.45 m height so the total time it took to reach the ground when it is shot horizontally given as

horizontal distance moved by arrow is given as

Part b)

If arrow is shot at an angle 30 degree such that it will hit the target at same height

so the range of the arrow is given as

Part c)

Now for maximum possible range the angle at which arrow is shot is given as 45 degree

so we will have

answer: 31, 5556. 952 seconds

energy stored in the capacitor= 9.72 x 10⁻⁴ j

explanation:

the energy stored in the capacitor is given by

e= 1/2 c v²

e= energy stored

c= capacitance= 1.5 µc= 1.5 x 10⁻⁶f

v= potential difference=36 v

so energy stored= e= 1/2 (1.5 x 10⁻⁶) (36)²

energy stored= 9.72 x 10⁻⁴j