Aboat with a mass of 1000 kg drifts with the current down a straight section of river parallel to the +x+x axis with a speed of 2.0 m/s. at t=0t=0 the boat engages its engines, and accelerates at 2.7 \,\mathrm{m/s^2}2.7m/s2. if the boat is oriented with its nose 45^\circ45∘ from the +x+x axis, which of the following is a possible value for the boat's momentum at t = 3.0\, \mathrm{s}t=3.0s after the engine had started?

pick the correct answer

a. \vec{p} = (7700 \hat{i} + 5700 \hat{j}) \; \mathrm{kg \, m/s}p=(7700i^+5700j^)kgm/s
b. \vec{p} = (9500 \hat{i} - 1400 \hat{j}) \; \mathrm{kg \, m/s}p=(9500i^−1400j^)kgm/s
c. \vec{p} = (5700 \hat{i} + 9500 \hat{j}) \; \mathrm{kg \, m/s}p=(5700i^+9500j^)kgm/s
d. \vec{p} = ( 1400 \hat{i} - 7700 \hat{j}) \; \mathrm{kg \, m/s}p=(1400i^−7700j^)kgm/s
e. none of these are correct

Askydiver weighing 140 lb (including equipment) falls vertically downward from an altitude of 19,000 ft and opens the parachute after 18 s of free fall. assume that the force of air resistance, which is directed opposite to the velocity, is of magnitude 0.55|v| when the parachute is closed and is of magnitude 14|v| when the parachute is open, where the velocity v is measured in ft/s. assume that acceleration due to gravity has magnitude 32 ft/s/s; remember that weight is the product of mass and gravitational acceleration. (a) find the speed of the skydiver when the parachute opens. (b) find the distance fallen before the parachute opens. (c) what is the limiting velocity vl after the parachute opens? (d) determine how long the sky diver is in the air after the parachute opens. (e) plot the graph of velocity versus time from the beginning of the fall until the skydiver reaches the ground.

(**i would really appreciate if this was answered soon** ) which pair of quantities includes one quantity that increases as the other decreases during simple harmonic motion?

You throw a baseball directly upward at time =0 at an initial speed of 14.9 m/s. what is the maximum height the ball reaches above where it leaves your hand? ignore air resistance and take =9.80 m/s2.