If x =(20-4t^2) find average velocity between t=0and t=2sec

The average velocity is 8 unit per sec

Explanation:

Given as :

The Distance x = 20 - 4t²  unit

Change in time Δt = ( 2 - 0 ) s = 2 s

Let the velocity = V unit/s

∴   V =

Or, V =  - 8t          unit/s

Now velocity at t = 0

V1 = - 8 × 0 =  0  unit/s

And   velocity  at t = 2 sec

V2 =  - 8 × 2 = - 16

So, Average velocity = = = -8

Or, = 8   unit/sec

Hence The average velocity is 8 unit per sec       Answer

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