Aman applies a torque to a nut with a wrench 0.350 m long. because of the cramped space, he must exert a force upward at an angle of 62.0° with respect to a line from the nut through the end of the wrench. if the force he exerts has magnitude 52.0 n, what magnitude torque (in n · m) does he apply to the nut? (assume that the force is applied at the end of the wrench.)

Explanation:

It is a problem to find the torque but the force applied was performed angularly. In this way the only component that will serve us is the one found in the line of rotation of the object.

Since the force is realized from upward with respect to a line from the bolt through the end of the wrench, we have the component described by Sin (\ theta). The force is performed on the opposite side of the angle, then

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s