An average human weighs about 600 n
if two such generic humans each carried 1.5 coulomb of excess charge, one positive and one negative, how far apart would they have to be for the electric attraction between them to equal their 600 n weight?

The distance between them, x = 5809.47 m

Explanation:

Given,

The average weight of a human, w = 600 N

The charge carried by the humans, q = 1.5 C

If 600 N of force acts between two opposite charges, the distance between the charges can be derived from the Coulomb's laws of force,

Where,

                          = 9 x 10⁹ N m² C⁻²

Therefore

                          x² = 9 x 10⁹ X 1.5² / 600

                              = 33750000

                           x = 5809.46 m

Hence, the distance between the humans should be, x = 5809.47 m

d

explanation:

v=uf/(u-f)

= 5.10/(5-10) convex lens has positive focal length

=50/-5

=-10 cm (formed at other side)

magnified images possible images can be real = projected onto a screen