The motion map shows an object’s position and velocity at given times. a long black arrow right labeled x. above that are 5 green arrows pointing right end to end and are the same length. there are two more green arrows each a little shorter. farther up from the line is a point. much farther above that are 3 green arrows each longer than the previous. how can the map be changed so it shows constant acceleration after the object changes direction? by adding vectors that are all the same length and placing them above the current top row of vectors by adding vectors that gradually increase in length and placing them above the current top row of vectors by adding vectors that are all the same length and placing them below the current bottom row of vectors by adding vectors that gradually increase in length and placing them below the current bottom row of vectors

    m₁v₁ + m₂v₂ = (m₁ + m₂)vmomentum is conserved.the left-hand side of the equation represents the momentum in the system before the collision.the right-hand side represents the momentum in the system after the collisionm₁ and v₁ represents the mass and the velocity of the physics blockm₂ and v₂ represents the mass and velocity of the ball of puttyv represents the final velocity of the combined mass.the question states the two masses stick together. they combined mass has its own velocity with the body mass the sum of the two objects' massestheir combined momentum is (m₁ + m₂)vto find the magitude of (m₁ + m₂)v, we need to add the vectors on the left-hand side of the equation: m₁v₁ + m₂v₂.note the diagram. i have positioned the vectors in accordance with their directions.the magnitude of the resultant can be calculated using the pythagorean theorem since this is a right triangle situation (north and west are perpendicular)|(m₁ + m₂)v| =  √[ (m₁v₁)² + (m₂v₂)² ]|(m₁ + m₂)v| =  √[ (1.5kg·8.0m/s)² + (0.40kg·20m/s)² ]|(m₁ + m₂)v| =  14.4 kg m/sfor two significant figures (assuming that 20m/s is two), this rounds to 14 kg m/s