An open train car, with a mass of 2010 kg, coasts along a horizontal track at the speed 2.53 m/s. the car passes under a loading chute and, as it does so, gravel falls vertically into it for 3.25 s at the rate of 423 kg/s. what is the car's speed after the loading is completed? ignore rolling friction.

v' = 1.5 m/s

Explanation:

Given that,

Mass of the car, m = 2010 kg

Speed of the car, v = 2.53 m/s

The car passes under a loading chute and gravel falls vertically into it for 3.25 s at the rate of 423 kg/s. Mass loaded during this time, m' = 1374.75 kg

Let v' is the speed of car after the loading is completed. Using the conservation of momentum to find it.

v' = 1.5 m/s

So, the speed of the car after the loading is completed is 1.5 m/s. Hence, this is the required solution.

f=ma newton

f=100x2.5=250n

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer