The expanding gases that leave the muzzle of a rifle also contribute to the recoil. a .30 caliber bullet has mass 7.20×10−3 kg and a speed of 601 m/s relative to the muzzle when fired from a rifle that has mass 3.00 kg. the loosely held rifle recoils at a speed of 1.95 m/s relative to the earth.
find the momentum of the propellant gases in a coordinate system attached to the earth as they leave the muzzle of the rifle.

Mg= 1.3418 kg*m/s

Explanation:

Mass of rifle

Recoil velocity of rifle

Momentum of rifle

mass of bullet

mb=7.2x10^{-3} kg=0.0072 kg

velocity of bullet relative to muzzel

v_{b} = 601 m/s

velocity of bullet relative to earth= 601 - 1.95=599.05 m/s

momentum of bullet

the momentum of the propellant gases = momentum of rifle - momentum of bullet

the momentum of the propellant gases

Mg=5.655 -4.3132

Mg= 1.3418 kg*m/s

the momentum of the propellant gases in a coordinate system attached to the earth as they leave the muzzle of the rifle is 1.3418 kgm/s

as we probably am aware that our atmosphere or air have various levels, each level has different gasses, and each gas has another porousness. at the point when the light originates from lower porousness to higher penetrability, it alters its course. with the goal that implies that when the light originates from the moon to the earth, it alters it's course a lot more occasions. it essentially implies that the state of the light piece of the moon is changed on the earth.

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