Calculate the ratio of the drag force on a passenger jet flying at an altitude of 10 km to the drag force on a prop-driven plane flying at two-fifths the speed and half the altitude of the jet. at 10 km the density of air is 0.380 kg/m3 and at 5.0 km it is 0.670 kg/m3. the prop-driven plane has one-third the cross-sectional area of the passenger jet. the passenger jet has two-fifths the drag coefficient of the prop-driven plane.

2.268

Explanation:

The concepts that we need to use here for give a solution are Drag coefficient and drag force.

Drag force is given by,

Where,

c is the drag coefficient

is the density

A cross sectional area

V the velocity.

Our values for this problem are divided for Passenger and Driver.

For Jet are:

For prop-driven are:

From the problem we need to assume that and , THEN

Applying to each case the Drag force equation we have,

The ratio between the two force is,

Therefore the force experienced by a Jet pilot under these conditions is 2,268 times greater than that of a prop-driven

magnified images possible images can be real = projected onto a screen

d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day