Ashopper in a supermarket pushes a loaded cart with a horizontal force of 11 n. the cart has a mass of 35 kg. the acceleration of gravity is 9.8 m/s 2 . disregarding friction, how far will the cart move in 3.5 s, starting from rest? answer in units of m.

s = 1.925 meters

Explanation:

Given that,

Horizontal force acting on the cart, F = 11 N

Mass of the cart, m = 35 kg

To find,

Distance covered by the cart in 3.5 seconds if it starts from rest.

Solution,

As the cart is starting from rest, u = 0

Let x is the distance moved by the cart. It can be calculated using the second equation of motion as :

Since,

s = 1.925 meters

Therefore, the distance covered by the cart is 1.925 meters.

i believe the answer is a hope it and is correct

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

where is unknown. because the position is parabolic, there is symmetry about the midpoint at , and we know that

so that the position function is

which means the velocity is

then the total distance traveled is

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at and ends at , so its displacement is 0.