An engineer is designing a spring to be placed at the bottom of an elevator shaft. if the elevator cable should happen to break when the elevator is at a height h = 12.5 m above the top of the spring, calculate the value the spring constant k should have so that passengers undergo a maximum acceleration of 5.3g. take the mass of the elevators plus passengers to be m = 1439 kg.

Explanation:

As per energy conservation we know that

initial total gravitational potential energy = final spring potential energy

so we have

also we know that maximum acceleration will be 5.3 g

so it is given as

so we have

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hi there!

out of the two, (b) precision would be more reasonable.   however, both a and b could be pretty reasonable.

-awesomerepublic   : )