Apiece of metal has attained a velocity of 107.8 m/sec after fallinf for 10 seconds what is its initial velocity

7.8 m/s

Explanation:

Here object is falling with a gravitational acceleration there  for we can take acceleration = 10 m/ s² and its constant through out the motion there for we can use motion equation

V = U + at

V - Final velocity

U - Initial velocity

a - acceleration

t - time

V=U+at

107.8=U + 10×10

  = 7.8 m/s

trig 15.3 cos

what is the speed of a softball that travels 20m in 2secs

speed = 20/2 = 10 m/s