An object consists of a rod (of length 4.0 m and negligible moment of inertia) to which five small 1.0-kg massesare attached, one at each end and one at each point on the rod 1.0 m from each end. (the masses are one meterapart.) the moment of inertia of this object about an axis perpendicular to the rod and through one of the endmasses

I = 30 kg m²

Explanation:

given,

length of rod = 4 m

mass of the 5 small masses = 1 kg

masses are kept at an interval of 1 m

Moment of inertia of the object = ? from the end mass

now distance of the masses from the end

r₁ = 1 m    r₂ = 2 m   r₃ = 3 m  r₄ = 4 m

hence, the moment of inertia

I = I₁ + I₂ + I₃ + I₄ + I₅

I = mr₁²+ mr₂² + mr₃² + mr₄² + mr₅²

I = 1 x 0²+ 1 x 1² + 1 x 2²+ 1 x 3² + 1 x 4²

I = 1  + 4+ 9 + 16

I = 30 kg m²

hence, the moment of inertia of the object is I = 30 kg m²

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hope this you out ^w^

u=13

v=30

s/t=u+1\2at

=13+431/2

=13+265.5

=278.5