Acrate is lifted vertically 1.5 m and then held at rest. the crate has weight 100 n (i. e., it is reese (enr647) – hs onramps 04: intro to work and energy – mcdaniel – (34472020) 2 supported by an upward force of 100 n). how much work is being done to hold the crate 1.5 m above the ground in this way?

150Joules

Explanation:

Work is said to be done if a force is applied to cause a body to move through a distance.

Work done = Force × distance

Given force = 100N

Distance = 1.5m

Work done = 100 × 1.5

Work done = 150Joules.

the small 0.38-kg slider is known to move from position a to position b along the vertical-plane slot. determine (a) the work done on the body by its weight and (b) the work done on the body by the spring. the distance r = 0.70 m, the spring modulus k = 154 n/m, and the unstretched length of the spring is 0.53 m

explanation:

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