At amusement parks, there is a popular ride where the floor of a rotating cylindrical room falls away, leaving the backs of the riders plastered against the wall. suppose the radius of the room is 3.6 meters and the coefficient of friction between the rider and the wall is 0.720. what is the minimum the safe speed of the wall for the rider not to drop when the floor falls? use g=9.8m/ s^2

7m/s

Explanation:

To solve this problem it is necessary to remember the concepts related to Centripedal force, normal force and frictional force.

The centripetal force is given by:

Where,

m=mass

v= velocity

R= Radius

On the other hand the Friction Force is given by,

In order for the Riders to maintain a vertical balance the force relative to the weight and friction must be equal, so

In the particular case of the movement the centripetal Force is equal to the normal force, thus, replacing

Re-arrange the velocity,

Replacing our values we have that,

this is a good question! i'll do some research and come back when i have the answer!

the answer would be 32*f