Atypical coal-fired power plant burns 350 metric tons of coal every hour to generate 2.6×106 mj of electricity. 1 metric ton = 1000 kg; 1 metric ton of coal has a volume of 1.5 m3. the heat of combustion is 28 mj/kg. assume that all heat is transferred from the fuel to the boiler and that all the work done in spinning the turbine is transformed into electrical energy. what is the power plant's thermal efficiency?

0.00095%

Explanation:

Mass of coal needed every day = Mass needed every hour × 24

Thermal energy released per hour = Mass × Heat of combustion

Power released per second = Energy / 3600 seconds

Thermal efficiency = (Electrical power / Mechanical power) × 100

Thermal efficiency of the plant is 0.00095%

when two balls of the different masses are dropped from equal height, they reach the ground at the same time .this is because they experience the same acceleration.

the acceleration is independent of mass.

thus when they are dropped they will always maintain the same velocity and travel the same distance (neglect air resistance of course) at the same time.