A9.0 g wad of sticky clay is hurled horizontally at a 90 g wooden block initially at rest on a horizontal surface. the clay sticks to the block. after impact, the block slides 7.50 m before coming to rest. if the coefficient of friction between block and surface is 0.650, what was the speed of the clay (in m/s) immediately before impact?

107.58 m/s

Explanation:

from the question we are given the following:

mass of the stick (M₁)= 9 g = 0.009 kg

mass of the block (M₂)= 90 g = 0.09 kg

total mass (M₁+M₂) = 99 g = 0.099 kg

distance (s) = 7.5 m

coefficient of friction (Uk) = 0.650

acceleration due to gravity (g) = 9.8 m/s^{2}

apply the equation below

change in kinetic energy = net work done

final kinetic energy(K₂) - final kinetic energy(K₁) = Uk x force(F) x distance(s)

final kinetic energy is zero because the clay and the wood comes to a stop

kinetic energy = 0.5 x m x v^{2} and

force = m x g so the equation now becomes

0.5 x m x v^{2} = Uk x m x g x s

0.5 x 0.099 x v^{2} = 0.650 x 0.099 x 9.8 x 7.5

V = 9.78 m/s

from the conservation of momentum

M₁ V₁ + M₂ V₂ = (M₁ + M₂ ) V

V₂  is zero since the block is initially at rest, so our equation becomes

M₁ V₁ = (M₁ + M₂ ) V

0.009 x V₁ = 0.099 x 9.78

V₁ = 107.58 m/s

the speed of the clay before impact is 107.58 m/s

i just did an experiment like this in my science class. also the answer is yes, it will get separated because they are two opposites meaning if they are opposite they can not attract.

hope this .!

i believe the answer is electric potential.

explanation: