Apositive charge of 6.0 × 10-4 c is in an electric field that exerts a force of 4.5 × 10-4 n on it. what is the strength of the electric field?

0.75 NC⁻¹

Explanation:

Electric field intensity ( or strength of the electric field ) is the force per a 1 C charge,

So, Force (F) = Electric field intensity(E) × Charge (q)

                 F = E×q ⇒ q = F/E

                                      = 4.5×10⁻⁴/6×10⁻⁴ = 0.75 NC⁻¹

According to cool om's law electric fields are generated due to charges. When charges are same there is a repulsive force acted on both charges. When charges are opposite there is a attraction force acted  on both charges.

According to cool om's law,

F =G×q1×q2 / r²

F = force exerted of two charges

q1 , q2 = charges

r = distance between two charges

And also Electric field intensity is a vector which has a magnitude and direction both. Direction is depending on a charge and the sign of the charge

v=ir = 3x15 =45 v

its c i just checked it