The 2000-kg cab of a freight elevator is rated to carry a maximum load of 1200 kg, but a careless worker fills the cab with freight that has a combined inertia of 1400 kg. the worker then raises the cab 3.1 m at a steady 2.0 m> s. you notice an unfamiliar whine and come over to investigate. as supervisor, you know that the motor has a 10% tolerance in its rated power output, and you must decide whether there’s going to be trouble.

do you have a formula possibly

-4 on

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s