An optical disk drive in your computer can spin a disk up to 10,000 rpm (about 1045 rad/s ). if a particular disk is spun at 470.2 rad/s while it is being read, and then is allowed to come to rest over 0.569 seconds , what is the magnitude of the average angular acceleration of the disk?

826.36203 m/s²

Explanation:

= Final angular velocity = 470.2 rad/s

= Final angular velocity = 0

= Angular acceleration

t = Time taken

Equation of rotational motion

Magnitude of the average angular acceleration of the disk is 826.36203 m/s²

graphing motion: mastery test

209be

what is the instantaneous acceleration of

the particle at point b?

0 meters/second?

10 meters/second?

12 meters/second?

velocity imetersisecond

15 meters/second?

20

time (seconds)

answer: 0 meters/second^2

c) up

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