50-g of hot water at 65 degree c is poured into a cavity in a very large block of ice at 0 degrees c. the final temperature of the water in the cavity is then 0 degrees c. what is the mass of the ice that melts?
solve using calories. show equations, units, and work.

m = 40.88 g

Explanation:

Given data:

We know that Ice at zero degree celcius convert into liquid form by observing heat

latent heat of fusion = 79.5 cal/g

heat required or relaesed to convert 50 gram of water at 65 degree  c to zero degree celcius

let mass of ice is m

where 1 cal/g  os specific heat of water

solving for m

m = 40.88 g

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