Suppose that an ion source in a mass spectrometer produces doubly ionized gold ions (au2+), each with a mass of 3.27 × 10-25 kg. the ions are accelerated from rest through a potential difference of 1.90 kv. then, a 0.540-t magnetic field causes the ions to follow a circular path. determine the radius of the path.

Radius of the path is  

Explanation:

It is given that gold is doubly ionized

Charge

Mass of the each ion =

So total mass m =

Potential difference V = 1.9 KV

Magnetic field B = 0.540 T

We know that

We have to find the radius of the path

We know that radius of the path is given by

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