For a spring oscillating in simple harmonic motion, at what point will the velocity of
the spring be greatest?

equilibrium position.

Explanation:

In simple harmonic motion , velocity v(t) is given by,

v(t) = -ω A sin(ωt + φ)

where

ω = angular velocity of the corresponding circular motion

A = amplitude

t = time

φ = the initial angle of the corresponding circular motion when the motion begin.

v (t) get maximized when sin value is maximized , i.e. sin =1

The particle has maximum speed when it passes through the equilibrium position.

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i think it's 35 meters