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Physics, 15.11.2019 20:31 ellisc7044

Consider two particles a and b. the angular position of particle a, with constant angular acceleration, depends on time according to \theta_{\rm a}(t)=\theta_0+\omega_0t+\frac{_1}{ ^2}\alpha t^2. at time t=t_1, particle b, which also undergoes constant angular acceleration, has twice the angular acceleration, half the angular velocity, and the same angular position that particle a had at time t=0.which of the following equations describes the angular position of particle b? a) theta_{\rm b}(t)=\theta_0+2\omega_0t+\frac{1}{ 4}\alpha t^2b) theta_{\rm b}(t)=\theta_0+\frac{1}{2}\omega_0t +\alpha t^2c) theta_{\rm b}(t)=\theta_0+2\omega_0(t-t_1) +\frac{1}{4}\alpha (t-t_1)^2d) theta_{\rm b}(t)=\theta_0+\frac{1}{2}\omega_0( t-t_1)+\alpha (t-t_1)^2e) theta_{\rm b}(t)=\theta_0+2\omega_0(t+t_1) +\frac{1}{4}\alpha (t+t_1)^2f) theta_{\rm b}(t)=\theta_0+\frac{1}{2}\omega_0( t+t_1)+\alpha (t+t_1)^2

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