Aconductor carrying 14.7 amps of current is directed along the positive x-axis and perpendicular to a uniform magnetic field. a magnetic force per unit length of 0.125 n/m acts on the conductor in the negative y direction. what is the strength of the magnetic field at the place where the current is? 0.0001 t

B = 0.009 T

Explanation:

The magnetic force is given by

    F = q vx B = i L x B

Bold quantities refer to vectors.

We are given some data the current (i 14.7 A), the force per unit length (F/L= 0.125 N / m)

We can take off in magnetic field since the current and the field are perpendicular, so the sine 90 = 1, write the magnitude of the equation

F = i L B

B = (F / L) 1 / i

B = 0.125    1/14.7

B = 0.009 T

object 2 because all the other ones are wrong