9. a radioisotope has a half-life of 4.50 min and an initial decay rate of 8400 bq. what will be
the decay rate after 18.0 min?

525 Bq

Explanation:

The decay rate is directly proportional to the amount of radioisotope, so we can use the half-life equation:

A = A₀ (½)^(t / T)

A is the final amount

A₀ is the initial amount,

t is the time,

T is the half life

A = (8400 Bq) (½)^(18.0 min / 4.50 min)

A = (8400 Bq) (½)^4

A = (8400 Bq) (1/16)

A = 525 Bq

this is a good question! i'll do some research and come back when i have the answer!

if they have a finite resultant