Acar is traveling at 50.0 km/h on a flat highway.
(a) if the coefficient of friction between road and tires on a rainy day is 0.100, what is the minimum distance in which the car will stop?
(b) what is the stopping distance when the surface is dry and the coefficient of friction is 0.600?

total distance/total time

(85 + 82)/(5+3)

167/8

20 just over

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft