The conductive tissues of the upper leg can be modeled as a 40-cm-long, 12-cm-diameter cylinder of muscle and fat. the resistivities of muscle and fat are 13 ω m and 25 ω m, respectively. one person’s upper leg is 82% muscle, 18% fat. what current is measured if a 1.5 v potential difference is applied between the person’s hip and knee?

To calculate and solve the problem it is necessary to apply the concepts related to resistance and resistivity.

The equation that is responsible for relating the two variables is:

Where,

R= Resistance of the conductor

Resistivity of the conductor material

L = Length

A = Cross-sectional area of conductor

With the previous values the area of the muscle (Real Muscle-82%)is,

Using the equation from Resistance we have that at the muscle the value is:

At the same time we can make the same process to calculate the resistance of the fat, then

The resistance of the fat would be,

Then the total resistance in a set as the previously writen, i.e, in parallel is:

We can here apply Ohm's law, then

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west