You throw a bouncy rubber ball and a wet lump of clay, both of mass m, at a wall. both strike the wall at speed v, but while the ball bounces off with no loss of speed, the clay sticks. what is the change in momentum of the clay and ball, respectively, assuming that toward the wall is the positive direction? 0; mv mv; 0 0; −2mv −mv; −mv −mv; −2mv

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.

Then the answer would be d then