A6.0 mw vertically polarized laser beam passes through a polarizing filter whose axis is 75° from vertical. what is the laser-beam power after passing through the filter?

     I  =  0.4019 m W

Explanation:

given,                                      

Beam of light Intensity =  6.0 m W          

angle made with the vertical = 75°                  

Power of the laser beam passing through filter = ?

using formula                                            

                I  =  I₀  cos²(θ)            

I is the intensity required            

I₀ is the initial intensity of light

                I  =  I₀  cos²(θ)                        

                I  =  6 x  cos²(75°)                    

                I  =  6 x  0.0669              

                I  =  0.4019 m W                    

Laser beam power after passing through filter is equal to I  =  0.4019 m W

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