An object at rest on a flat, horizontal surface explodes into two fragments, one seven times as massive as the other. the heavier fragment slides 8.10 m before stopping. how far does the lighter fragment slide? part a assume that both fragments have the same coefficient of kinetic friction.

d_1 = 396.9 m

Explanation:

Given data:mass of lighter fragment m

Mass of heavier fragment = 7m

Velocity of lighter fragment  = V1

Velocity of heavier fragment  = V2

As object is rest before explosion occur thus momentum of system is zero

mv1 + 7mv2 = 0

V1 = -7V2

force of Friction on lighter fragment

force of friction on heavier fragment

Deceleration of lighter fragment = a1

we know that force of friction is given as

ma1 = - f1

Deceleration of heavier fragment = a2

7ma2 = -f2

Final velocity of  lighter fragment = V3 = 0 m/s

Final velocity of heavier fragment = V4 = 0 m/s

Distance traveled by lighter fragment prior to rest position is  = d1

Distance traveled by the heavier fragment prior to rest position is  = d2 = 8.10 m

d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day