Aball thrown horizontally at vi = 26.0 m/s travels a horizontal distance of d = 52.0 m before hitting the ground. from what height h was the ball thrown?

20 m

Explanation:

We can use the kinematic equation,

s = ut +½at²

Where

s = displacement

u = initial velocity

t = time taken

a = acceleration

Using the equation in the horizontal direction,

52 = 26t +½×0×t²,. a = 0 because no unbalanced force act on object in that direction

So t = 2 s

Then using the equation in vertical direction,

s = 0×t +½×g×2², u = 0 because initial vertical velocity is 0

We get,

s = 20 m