Acube of ice at an initial temperature of -15.00°c weighing 12.5 g total is placed in 85.0 g of water at an initial temperature of 25.00°c. when thermal equilibrium is achieved, the final temperature is 22.24°c. what is the specific heat capacity of ice?

The specific heat of ice is 2.11 J/g°C

Explanation:

When ice is mixed with water, the amount of heat released by water will be equal to the amount of heat absorbed by ice.

The equation used to calculate heat released or absorbed follows:

      ......(1)

where,

q = heat absorbed or released

= mass of ice = 12.5 g

= mass of water = 85.0 g

= final temperature = 22.24°C

= initial temperature of ice = -15.00°C

= initial temperature of water = 25.00°C

= specific heat of ice = ?

= specific heat of water = 4.186 J/g°C

Putting values in equation 1, we get:

Hence, the specific heat of ice is 2.11 J/g°C

the order for strong to weak forces such as

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force

the fundamental forces are those forces that act between to objects or element to make interactions. there are four types of fundamental forces such as strong and weak nuclear forces (due to protons and electrons), electromagnetic force (due to the motion of electrons) and gravitational force (due to orbital movement of the planet). if these forces are arranged on the basis of their maximum strength then the order is

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force