The propeller of a world war ii fighter plane is 2.30 m in diameter. what is its angular velocity in radians per second if it spins at 1200 rev/min? what is the linear speed of its tip at this angular velocity if the plane is stationary on the tarmac? what is the centripetal acceleration of the propeller tip under these conditions? calculate it in meters per second squared and convert to multiples of g.

- the angular velocity in radians per second is 125.7 rad/s

- the centripetal acceleration of the propeller tip under these conditions is 144.5 m/s

- the centripetal acceleration of the propeller tip under these conditions in multiplied of g is 1853 g

Explanation:

given information:

diameter. d = 2.30 --> r = d/2 = 2.3/2 = 1.15 m

angular velocity, ω = 1200 rev/min

- angular velocity in radians per second

ω = 1200 rev/min

   = 1200

   = 125.7 rad/s

-  the linear speed of its tip at this angular velocity

v = ω r

  = 125.7 rad/s x 1.15 m

  = 144.5 m/s

- the centripetal acceleration

a = ω^2 r, ω =

  =

  =

  =

  = 18160

covert to multiplei of g, g= 9.8

a = 18160 /9.8 = 1853 g

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2