A108 kg clock initially at rest on a horizontal floor requires a 639 n horizontal force to set it in motion. after the clock is in motion, a horizontal force of 521 n keeps it moving with a constant velocity.

Explanation:

It is given that,

Mass of the clock, m = 108 kg

Force acting on it when it is in motion,

After the clock is in motion, a horizontal force of 521 N keeps it moving with a constant velocity, F' = 521 N

It is assumed to find the coefficient of between the clock and the floor. The force of friction is given by :

So, the coefficient of static friction between the clock and the floor is 0.6. Hence, this is the required solution.

jupiter is the largest planet in our solar system, having a mass and radius that are respectively, 318 and 11.2 times that of earth. suppose that an object falls from rest near the surface of each planet and that the acceleration due to gravity remains constant during the fall. each object falls the same distance before striking the ground. determine the ratio of the time of fall on jupiter to that on earth.