The space capsule has a mass of 1200 kg and a moment of inertia ig = 900 kg·m2 about an axispassing through g and directed perpendicular to the page. if it is traveling forward with a speed vg = 800 m/s and executes a turn by means of two jets which provide a constant thrust of 400 n for 0.3 s, determine the capsule's angular velocity just after the jets are turned off.

can you explain what has done here?

Explanation:

Angular impulse = change in angular momentum

Mg Δt = ΔHg

Mg Δt = Hg₂ − Hg₁

Rearranging, initial angular momentum + angular impulse = final angular momentum

Hg₁ + Mg Δt = Hg₂

Initially, the rocket is not turning, so ω₁ = 0 rad/s.

Hg₁ = I ω₁

Hg₁ = (900 kg m²) (0 rad/s)

Hg₁ = 0 kg m²/s

The total moment applied is the sum of the perpendicular components of each force multiplied by the distance.  Take counterclockwise to be positive.

Mg = (400 N cos 15° × 1.5 m) + (400 N cos 15° × 1.5 m)

Mg = 2 (400 N cos 15° × 1.5 m)

The time of the impulse Δt is 0.3 s.

The final angular momentum is the product of the moment of inertia and the final angular velocity.

Hg₂ = I ω₂

Hg₂ = (900 kg m²) ω₂

Plugging everything in:

0 kg m²/s + 2 (400 N cos 15° × 1.5 m) (0.3 s) = (900 kg m²) ω₂

ω₂ = 0.386 rad/s

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explanation:

there is no change in the electric potential energy as it is in rest on both conditions.

the temperature and the pressure affect solubility. temperature affects by changing the properties of the solvent. the increase in pressure increases solubility, the decrease in pressure decreases solubility.